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x^2-63x-4856=0
a = 1; b = -63; c = -4856;
Δ = b2-4ac
Δ = -632-4·1·(-4856)
Δ = 23393
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-\sqrt{23393}}{2*1}=\frac{63-\sqrt{23393}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+\sqrt{23393}}{2*1}=\frac{63+\sqrt{23393}}{2} $
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